y^2/(0.1)=4.0*10^-9

Solution for y^2/(0.1)=4.0*10^-9 equation:

y^2/(0.1)=4.0*10^-9

We move all terms to the left:

y^2/(0.1)-(4.0*10^-9)=0

We add all the numbers together, and all the variables

y^2/(0.1)-9-4.0E=0

We multiply all the terms by the denominator


y^2-9*(0.1)-(4.0E)*(0.1)=0

We add all the numbers together, and all the variables

y^2-9*(0.1)-(10.873127313836)*(0.1)=0

We add all the numbers together, and all the variables

y^2-1.9873127313836=0

a = 1; b = 0; c = -1.9873127313836;
Δ = b2-4ac
Δ = 02-4·1·(-1.9873127313836)
Δ = 7.9492509255344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{7.9492509255344}}{2*1}=\frac{0-\sqrt{7.9492509255344}}{2}
=-\frac{\sqrt{}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{7.9492509255344}}{2*1}=\frac{0+\sqrt{7.9492509255344}}{2}
=\frac{\sqrt{}}{2}
$